A bullet of mass m = 50 gm strikes ( Δ t ≈ 0)a sand bag of mass M = 5 kg hanging from a fixed point, with a horizontal velocity 
. If bullet sticks to the sand bag then just after collision the ratio of final & initial kinetic energy of the bullet is :
Text Solution
Verified by ExpertsThe correct answer is:
D
0.05 × v p + m × 0 = 5.05 v
∴ 
= 
= 10 –2 ⇒ 
= (10 –2 ) 2 = 10 –4 .
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